Master presentation

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Submitted by:Jafar HasanpoorChair of Committee:

 Stephen Morse Committee Member:

H.Scott Norville

 Investigating the behavior of Glass Plate on Partial support

by Finite Elements Method using Abaqus/CAE

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Element Type:1500 mm X 1000 mm X 12 mm Load:0.5 kPa

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Define Boundary Condition

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Define Boundary Condition

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Assign partial support

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Define load

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Results

76 in. X 38 in. X 0.472in. AR=0.5, Load = 20.88psf

K=13.8 MPa (2000 psi) Rigid Simply Supported

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K=400 psi

K=2.6 MPa (400 psi) Partially Supported

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K=64 psi

K=0.45 MPa (64 psi) Partially Supported

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K=16 psi

K=0.11 MPa (16 psi) Partially Supported

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K=4 psi

K=0.027 MPa (4 psi) Partially Supported

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K=.01 psi (Free edge)

K = 0 MPa (0.01 psi) Free edge

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Maximum stress- stiffness chart AR=.5

Free edge

Simply supported

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Displacement - Stiffness chart AR=.5

Free edge

Simply supported

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Same Stiffness

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AR=2, 38in X 76 in

Thickness=.47 in Thickness=.74 in

Load=10.44psf

Load=20.88psf

Load=41.77psf

Stress=1475 psi Stress=584 psi

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AR=1

AR=2

Stress=986.7psi

Stress=584.2 psi