2derivadas_1bachccss-nsloreto
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Ejercicios de Derivadas para 1º Bachiller CCSS (y 2) Calcular las derivadas de las siguientes funciones 1) x x x f cos ) ( + = senx x x f - = 2 1 ) ( ' 2) senx x x g 2 ) ( = x x xsenx x g cos 2 ) ( ' 2 + = 3) x senx x h cos ) ( ⋅ = x sen x x h 2 2 cos ) ( ' - = 4) x x x i cos ) ( 3 = senx x x x x i 3 2 cos 3 ) ( ' - = 5) 2 7 ) ( x x j x ⋅ = x x x j x x 2 7 7 ln 7 ) ( ' 2 ⋅ + ⋅ ⋅ = 6) 2 3 ) ( x e x k x ⋅ = ) 2 ( 3 ) ( ' + = x xe x k x 7) x x senx x x l cos ) ( + + = 2 ) cos ( ) 1 ( cos ) 1 ( 1 ) ( ' x x senx x x x x l + - + + + = 8) 2 3 ) 3 ( ) ( x x x m + = ) 3 3 )( 3 ( 2 ) ( ' 2 3 + + = x x x x m 9) 2 2 1 1 ) ( + = x x n 3 2 ) 1 ( 4 ) ( ' + - = x x x n 10) ) 4 ( ) ( 2 x x sen x o + = ) 4 cos( ) 4 2 ( ) ( ' 2 x x x x o + + = 11) x x sen x p 2 2 cos ) ( ⋅ = x sen x x senx x p 3 3 cos 2 cos 2 ) ( ' ⋅ - ⋅ = 12) x e x q 5 ) ( = x e x q 5 5 ) ( ' = 13) ) 7 ln( ) ( 2 x x r = x x r 2 ) ( ' = 14) senx x s = ) ( senx x x s 2 cos ) ( ' =
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Transcript of 2derivadas_1bachccss-nsloreto
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Ejercicios de Derivadas para 1 Bachiller CCSS (y 2)
Calcular las derivadas de las siguientes funciones
1) xxxf cos)( += senxx
xf =2
1)('
2) senxxxg 2)( = xxxsenxxg cos2)(' 2+=
3) xsenxxh cos)( = xsenxxh 22cos)(' =
4) xxxi cos)( 3= senxxxxxi 32 cos3)(' =
5) 27)( xxj x = xxxj xx 277ln7)(' 2 +=
6) 23)( xexk x = )2(3)(' += xxexk x
7) xx
senxxxl
cos)(
+
+=
2)cos(
)1(cos)1(1)('
xx
senxxxxxl
+
+++=
8) 23 )3()( xxxm += )33)(3(2)(' 23 ++= xxxxm
9) 2
2 1
1)(
+=
xxn
32 )1(
4)('
+
=
x
xxn
10) )4()( 2 xxsenxo += )4cos()42()(' 2 xxxxo ++=
11) xxsenxp 22 cos)( = xsenxxsenxxp 33 cos2cos2)(' =
12) xexq 5)( = xexq 55)(' =
13) )7ln()( 2xxr = x
xr2
)(' =
14) senxxs =)( senx
xxs
2
cos)(' =
-
15) )3ln()( 2 += xxt 3
)('2 +
=
x
xxt
16) 825)( = xxu 8255ln2)(' = xxu
17) )47cos()( xxv x += )47()47ln7()(' xsenxv xx ++=
18) 5 4)( xxw = 55
4)('
xxw =
19) xxxx =)( 2
3)('
xxx =
20) 3 2
)(x
xxy =
3 23
1)('
xxy =
21) 1
1)(
2
+=
x
xxz
2
2
)1(
12)('
=
x
xxxz
22) 3
3)(
2
2
+
=
x
xxa
22 )3(
12)('
+=
x
xxa
23) 5
7)(
+=
xxb
2)5(
7)('
+=
xxb
24) 2
)(+
=
x
xxc
2)2(
2)('
+
=
xxc
