columna resistencia de materiales
4
Columnas Columna de marco “A” P U =7000.12 kg M Z =16.375 kN−m=166921.5 kg−cm M x =−3.983 kN−m=40601 . 42 kg−cm d h =0.95 Pe x =Mz e x = Mz P = 166921.5 7000.121 =23.84 cm Pe z =Mx e z = Mx P = 40601.42 7000.121 =5.8 cm se propone una p=0 . 03 ∴ q=0.74 y A S =0.03 ( 40)( 35) =42 cm 2 e x h = 23.84 40 =0.596 e z b = 5.8 35 =0 . 1657 k x =0.59 k z =1.21 P RX =kF R bh 2 f '' c=( 0.59)( 0.8 )( 35)( 40)( 170 )=112336 kg P Rz =kF R bh 2 f '' c=( 1.21 )( 0.8 )( 35)( 40)( 170) =230384 kg P R 0 =F R [ f '' cA g + A s f y ] =( 0.8) [ 170 ( 35)( 40 ) +0 ]=190400 kg P R = 1 1 P RX + 1 P RZ + 1 P R 0 = 1 1 112336 + 1 230384 + 1 190400 =125151.05 P R >P U pasa l=3m estribos de 3 8 ″ s≤ 850 √ fy s≤ 850 √ 4200 =13. 11cm s≤ b 2 s≤ 35 2 =17.5 s≤48θ s≤48 ( 0.95 )=45.6 cm l= 300 6 =50 cm l=600 mm=60cm se toma el valor mayor de l que es de 60 cm. h=40cm
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reistencia de una columna
Transcript of columna resistencia de materiales
Columnas Columna de marco “A”
PU=7000 .12kgMZ=16 . 375kN−m=166921 .5kg−cmM x=−3 . 983kN−m=40601.42kg−cmdh
=0 .95
Pex=Mz ex=MzP
=166921 . 57000 .121
=23 . 84cm
Pez=Mx ez=MxP
=40601 . 427000 .121
=5. 8cm
se propone una p=0 .03 ∴ q=0 .74 y AS=0 . 03 (40 ) (35 )=42cm2
e xh
=23 . 8440
=0 . 596 ezb
=5. 835
=0 .1657
k x=0 .59 kz=1 . 21
PRX=kF Rbh2 f ' 'c= (0.59 ) (0 . 8 ) (35 ) ( 40 ) (170 )=112336 kg
PRz=kF R bh2 f ' 'c= (1. 21 ) (0. 8 ) (35 ) (40 ) (170 )=230384kg
PR0=F R [ f ' 'cA g+As f y ]=(0 . 8 ) [170 (35 ) ( 40 )+0 ]=190400kg
PR=11PRX
+1PRZ
+1PR0
=11112336
+1230384
+1190400
=125151 . 05
PR>PU pasa l=3m
estribos de 3
8″
s≤850
√ fy s≤850
√4200=13 . 11cm
s≤b2
s≤352
=17 . 5
s≤48θ s≤48 (0 . 95 )=45 .6 cm
l=3006
=50cm
l=600mm=60cmse toma el valor mayor de l que es de 60 cm .h=40cm
Columna “B”
PU=11580. 778kgMZ=26 . 9kN−m=274209 .98 kg−cmM x=9 .790kN−m=99796 . 126kg−cmdh
=0 .95
Pex=Mz ex=MzP
=274209 . 9811580 .778
=23 .67 cm
Pez=Mx ez=MxP
=99796 . 12611580. 778
=8 .62cm
se propone una p=0 .03 ∴ q=0 .74 As=0 .03 (40 ) (35 )=42cm2
e xh
=23 . 6740
=0 .6 ezb
=8. 6235
=0 .25
k x=0 .5 8 k z=1.01
PRX=kF Rbh2 f ' 'c= (0.58 ) (0 . 8 ) (35 ) ( 40 ) (170 )=110432kg
PRz=kF R bh2 f ' 'c= (1. 01 ) (0. 8 ) (35 ) (40 ) (170 )=192304 kg
PR0=F R [ f ' 'cA g+A s f y ]=(0 . 8 ) [170 (35 ) ( 40 )+0 ]=190400 kg
PR=11PRX
+1PRZ
+1PR0
=11110432
+1192304
+1190400
=111069.82
PR>PU pasa l=3m
estribos de 3
8″
s≤850√ fy
s≤850√4200
=13 . 11cm
s≤b2
s≤352
=17 . 5
s≤48θ s≤48 (0 . 95 )=45 .6 cm
l=3006
=50cm
l=600mm=60cmse toma el valor mayor de l que es de 60 cm .h=40cm
Columna marco “C”
PU=5544 .353kgMZ=14 . 402kN−m=146809 . 37kg−cmM x=2 .145 kN−m=21865.44 kg−cmdh
=0 .95
Pex=Mz ex=MzP
=146809 . 375544 .353
=26 . 48cm
Pez=Mx ez=MxP
=21865 . 445544 . 353
=3 . 94cm
se propone una p=0 .03 ∴ q=0 .74 As=0 .03 (40 ) (35 )=42cm2
e xh
=26 . 4840
=0 . 6 6 e zb
=3 .9435
=0. 11
k x=0 .5 5 k z=1 . 39
PRX=kF Rbh2 f ' 'c= (0.55 ) (0 . 8 ) (35 ) ( 40 ) (170 )=104720kg
PRz=kF R bh2 f ' 'c= (1. 39 ) (0 .8 ) (35 ) (40 ) (170 )=264656 kg
PR0=F R [ f ' 'cA g+A s f y ]=(0 . 8 ) [170 (35 ) ( 40 )+0 ]=190400 kg
PR=11PRX
+1PRZ
+1PR0
=11104720
+1264656
+1190400
=123828 . 84
PR>PU pasa l=3m
estribos de 3
8″
s≤850√ fy
s≤850√4200
=13 . 11cm
s≤b2
s≤352
=17 . 5
s≤48θ s≤48 (0 . 95 )=45 .6 cm
l=3006
=50cm
l=600mm=60cmse toma el valor mayor de l que es de 60 cm .h=40cm
Para todas las columnas
AS=42cm2
∴ son 2 varillas de {1
' '
=10 . 14 en cada cara ¿
