7/30/2019 Maxima Eficiencia Hidraulica de Un Canal Parabolico

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MAXIMA EFICIENCIA HIDRAULICA DE UN CANAL PARABOLICO

A = (2/3) TY . (1) P = T + (8Y2)/(3T) (2) T = P - (8Y2)/(3T) (3)

(3) en (1):

A = (2/3)PY - (16/9)(Y3/T) ..(4)

Derivando (4) respecto a Y:

0 = (2/3)P (16/3)(Y2/T) .(5) P = 8Y2/T .(6)

(2) en (6):

T = 4Y/(1/3)(1/2) .(7)

(7) en (1):

A = 8/3Y2/(1/3)(1/2) ..(8)

(7) en (6) :

P = 2Y/(1/3)(1/2) .(9)

Radio Hidrulico (A/P)

RH = 4/9Y (10)

7/30/2019 Maxima Eficiencia Hidraulica de Un Canal Parabolico

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