Mecanismos Practica
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Transcript of Mecanismos Practica
7/23/2019 Mecanismos Practica
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Mecanismos: Practica Califcada
Alumno :Hugo Alfredo Salazar Monterroso
En Matlab:
clc,clear
clear
AM=[0,0,0,0,0,0,0,0,0,0,0];
chi=0;
% a+b-c-d=0 a=0.15; %longitud del eslabon 2
b=0.2121; %longitud del eslabon
c=0.2!"!; %longitud al eslabon #
d=0.20#"; %longitud d eslabon $
&=0.1##"; %longitud del eslabon '
g=0.1##"; %longitud al eslabon '
t2=0.()i*1!0;
t=150.()i*1!0;
t#=0.()i*1!0;
t5="0.()i*1!0;
t'=1!0.()i*1!0;
2=10;
al&a2=1;&or i=1
&1=a.(cost2/-b.(cost/+c;
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&2=a.(sint2/-b.(sint/;
&=d.(cost-15()i*1!0/-&.(cost'/-g.(cost5/;
&#=d.(sint-15()i*1!0/-&.(sint'/-g.(sint5/;
A=[b.(sint/ -1 0 0;
-b.(cost/ 0 0 0;
-d(sint/ 0 &(sint'/ -cost'/;
d(cost/ 0 -&(cost'/ -sint'/]; =-[a.(cost2/-b.(cost/+c;a.(sint2/-b.(sint/;
d.(cost-15()i*1!0/-&.(cost'/-g.(cost5/;d.(sint-15()i*1!0/-
&.(sint'/-g.(sint5/];
=inA/(;
t=1/;
c=2/;
t'=/;
&=#/;
e=0.01;
hile abst/e 3 abst'/e
t=t+t;% ariacion de tetha =t
c=c+c;
t'=t'+t';% ariacion de tetha ' =t'
&=&+&;
&1=a.(cost2/-b.(cost/+c;
&2=a.(sint2/-b.(sint/;
&=d.(cost-15()i*1!0/-&.(cost'/-g.(cost5/;
&#=d.(sint-15()i*1!0/-&.(sint'/-g.(sint5/;
A=[b.(sint/ -1 0 0;
-b.(cost/ 0 0 0;
-d(sint/ 0 &(sint'/ -cost'/;
d(cost/ 0 -&(cost'/ -sint'/];
=-[a.(cost2/-b.(cost/+c;a.(sint2/-b.(sint/;
d.(cost-15()i*1!0/-&.(cost'/-g.(cost5/;d.(sint-15()i*1!0/-
&.(sint'/-g.(sint5/];
=inA/(;
t=1/;
c=2/;
t'=/;
&=#/;
%elocidades , el, ', el'
%&5=-a(2.(sint2/+b((sint/+el=0;
%&'=a(2.(cost2/-b((cost/=0;
%&=-d(.(sint-15()i*1!0/+&('(sint'/-el'(cost'/=0;
%&!=d(.(cost-15()i*1!0/-&('(sint'/-el'(sint'/=0;
4=[b.(sint/ -1 0 0;
-b.(cost/ 0 0 0;
-d(sint/ 0 &(sint'/ -cost'/;
d(cost/ 0 -&(cost'/ -sint'/];
$=[a(2(sint2/;-a(2(cost2/;0;0];
=in4/($;
=1/;
el=2/;
'=/;
el'=#/;
%aceleraciones al&a ace al&a' ace'
%&"=-a(al&a2(sint2/-
a(262(cost2/+b(al&a(sint/+b(62(cost/=0;
%&10=a(al&a2(cost2/-a(262(sent2/-
b(al&a(cost/+b(62(sint/=0;
%&11=-d(al&a(sint-15()i*1!0/-d(62(cost-
15()i*1!0/+&(al&a'(sint'/+&('62(cost'/+2(el'('(sint'/-
ace'(cost'/=0;
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%&12=d(al&a(cost-15()i*1!0/-d(62(sint-15()i*1!0/-
&(al&a5(cost'/+&('62(sent'/-2(el'('(cost'/-ace'(sint'/=0;
4a=[b.(sint/ -1 0 0;
-b.(cost/ 0 0 0;
-d(sint/ 0 &(sint'/ -cost'/;
d(cost/ 0 -&(cost'/ -sint'/];
7=[a(al&a2(sint2/+a(262(cost2/-b(62(cost/; -a(al&a2(cost2/+a(262(sint2/-b(62(sint/;
d(62(cost-15()i*1!0/-&('62(cost'/-2(el'('(sint'/;
d(62(sint-15()i*1!0/-&('62(sint'/+2(el'('(cost'/];
8=in4a/(7;
al&a=81/;
ace=82/;
al&a'=8/;
ace'=8#/;
end
M1=[t2(1!0*)i,t(1!0*)i,t'(1!0*)i,,el,',el',al&a,ace,al&a',el
'];
i& chi==0
AM=M1;
chi=1;
else
AM=[AM;M1];
end
t2=t2+5()i*1!0;
end
dis) 9 t2 t t' el ' el' al&a ace al&a' ace' 9/
dis) AM/
t2=AM,1/;
t=AM,2/;
t'=AM,/;
=AM,#/;
el=AM,5/;
'=AM,'/;
el'=AM,/;
al&a=AM,!/;
ace=AM,"/;
ala&'=AM,10/;
ace'=AM,11/;
Resultados:
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