MRUV
Transcript of MRUV
![Page 1: MRUV](https://reader033.fdocuments.es/reader033/viewer/2022051413/559707641a28ab932f8b45da/html5/thumbnails/1.jpg)
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Velocidad NO es constante
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Velocidad NO es constante
Cambios de velocidad
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Velocidad NO es constante
Cambios de velocidad
Magnitud Dirección Sentido
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Magnitud de la velocidad
cambia
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Magnitud de la velocidad
Aumentacambia
Disminuye
o
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Magnitud de la velocidad
Aumentacambia
Disminuye
o
¿cómo cambia?
![Page 10: MRUV](https://reader033.fdocuments.es/reader033/viewer/2022051413/559707641a28ab932f8b45da/html5/thumbnails/10.jpg)
¿de qué forma aumenta o disminuye?
Magnitud de la velocidad
Aumentacambia
Disminuye
o
¿cómo cambia?
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¿de qué forma aumenta o disminuye?
Magnitud de la velocidad
Aumentacambia
Disminuye
o
UNA CANTIDAD CONSTANTE CADA UNIDAD DE TIEMPO
¿cómo cambia?
![Page 12: MRUV](https://reader033.fdocuments.es/reader033/viewer/2022051413/559707641a28ab932f8b45da/html5/thumbnails/12.jpg)
10 m/s , 20 m/s, 30 m/s …Ejemplo:
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10 m/s , 20 m/s, 30 m/s …Ejemplo:
Varía una cantidad constante: 10 m/s
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10 m/s , 20 m/s, 30 m/s …Ejemplo:
Varía una cantidad constante: 10 m/s
uniforme
![Page 15: MRUV](https://reader033.fdocuments.es/reader033/viewer/2022051413/559707641a28ab932f8b45da/html5/thumbnails/15.jpg)
10 m/s , 20 m/s, 30 m/s …Ejemplo:
Varía una cantidad constante: 10 m/s
uniforme
La magnitud de la velocidad varía una cantidad constante
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Como hay cambios constantes en la velocidad…
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hay aceleraciónComo hay cambios constantes en la velocidad…
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hay aceleraciónComo hay cambios constantes en la velocidad…
constantey es
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hay aceleraciónComo hay cambios constantes en la velocidad…
cambio o variación de velocidad ( )
aceleraciónLa es un vectorque tiene la misma dirección y sentido del
v∆
constantey es
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0
0
tt
VV
t
va
f
f
−−
=∆∆=
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0
0
tt
VV
t
va
f
f
−−
=∆∆=
Variación de la velocidad:v∆:t∆ Variación del tiempo
:fV
:0V
Velocidad final
Velocidad inicial
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0
0
tt
VV
t
va
f
f
−−
=∆∆=
Si fV
0V
>
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0
0
tt
VV
t
va
f
f
−−
=∆∆=
Si fV
0V
> a
es positiva
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0
0
tt
VV
t
va
f
f
−−
=∆∆=
Si fV
0V
> a
es positiva Rapidezaumenta
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0
0
tt
VV
t
va
f
f
−−
=∆∆=
Si fV
0V
> a
es positiva
Si fV
0V
<
Rapidezaumenta
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0
0
tt
VV
t
va
f
f
−−
=∆∆=
Si fV
0V
> a
es positiva
Si fV
0V
< a
es negativa
Rapidezaumenta
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0
0
tt
VV
t
va
f
f
−−
=∆∆=
Si fV
0V
> a
es positiva
Si fV
0V
< a
es negativa
Rapidez
Rapidez
aumenta
disminuye
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En el Sistema internacional (S.I.): 2s
m
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En el Sistema internacional (S.I.): 2s
m
¿cómo surge esa unidad?
![Page 31: MRUV](https://reader033.fdocuments.es/reader033/viewer/2022051413/559707641a28ab932f8b45da/html5/thumbnails/31.jpg)
En el Sistema internacional (S.I.):
t
va
∆∆=
2s
m
¿cómo surge esa unidad?
![Page 32: MRUV](https://reader033.fdocuments.es/reader033/viewer/2022051413/559707641a28ab932f8b45da/html5/thumbnails/32.jpg)
En el Sistema internacional (S.I.):
t
va
∆∆=
ssm
2s
m
¿cómo surge esa unidad?
![Page 33: MRUV](https://reader033.fdocuments.es/reader033/viewer/2022051413/559707641a28ab932f8b45da/html5/thumbnails/33.jpg)
En el Sistema internacional (S.I.):
t
va
∆∆=
ssm
1
2s
m
¿cómo surge esa unidad?
![Page 34: MRUV](https://reader033.fdocuments.es/reader033/viewer/2022051413/559707641a28ab932f8b45da/html5/thumbnails/34.jpg)
En el Sistema internacional (S.I.):
t
va
∆∆=
ssm
1
2s
m
¿cómo surge esa unidad?
![Page 35: MRUV](https://reader033.fdocuments.es/reader033/viewer/2022051413/559707641a28ab932f8b45da/html5/thumbnails/35.jpg)
En el Sistema internacional (S.I.):
t
va
∆∆=
ssm
1ss
m
⋅=
2s
m
¿cómo surge esa unidad?
![Page 36: MRUV](https://reader033.fdocuments.es/reader033/viewer/2022051413/559707641a28ab932f8b45da/html5/thumbnails/36.jpg)
En el Sistema internacional (S.I.):
t
va
∆∆=
ssm
1ss
m
⋅=
2s
m=
2s
m
¿cómo surge esa unidad?
![Page 37: MRUV](https://reader033.fdocuments.es/reader033/viewer/2022051413/559707641a28ab932f8b45da/html5/thumbnails/37.jpg)
Otras:
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Otras:...,,
min,
222 sh
Km
h
Kmm
s
cm
⋅
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Si 20=a2s
m
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Si 20=a2s
m significa
![Page 42: MRUV](https://reader033.fdocuments.es/reader033/viewer/2022051413/559707641a28ab932f8b45da/html5/thumbnails/42.jpg)
Rapidez aumenta Si 20=a
2s
m significa20 m/s
cada segundo
![Page 43: MRUV](https://reader033.fdocuments.es/reader033/viewer/2022051413/559707641a28ab932f8b45da/html5/thumbnails/43.jpg)
Rapidez aumenta Si 20=a
2s
m significa20 m/s
cada segundo
Si 16−=a2h
Km
![Page 44: MRUV](https://reader033.fdocuments.es/reader033/viewer/2022051413/559707641a28ab932f8b45da/html5/thumbnails/44.jpg)
Rapidez aumenta Si 20=a
2s
m significa20 m/s
cada segundo
Si 16−=a2h
Km significa
![Page 45: MRUV](https://reader033.fdocuments.es/reader033/viewer/2022051413/559707641a28ab932f8b45da/html5/thumbnails/45.jpg)
Rapidez aumenta Si 20=a
2s
m significa20 m/s
cada segundo
Si 16−=a2h
Km significa16 Km/h
cada hora
Rapidez disminuye
![Page 46: MRUV](https://reader033.fdocuments.es/reader033/viewer/2022051413/559707641a28ab932f8b45da/html5/thumbnails/46.jpg)
Rapidez aumenta Si 20=a
2s
m significa20 m/s
cada segundo
Si 16−=a2h
Km significa16 Km/h
cada hora
Rapidez disminuye
El signo de la aceleración indica si la rapidez (magnitud de la velocidad) aumenta o disminuye
![Page 47: MRUV](https://reader033.fdocuments.es/reader033/viewer/2022051413/559707641a28ab932f8b45da/html5/thumbnails/47.jpg)
Dada la definición de la aceleración:
![Page 48: MRUV](https://reader033.fdocuments.es/reader033/viewer/2022051413/559707641a28ab932f8b45da/html5/thumbnails/48.jpg)
0
0
tt
VVa f
−−
=
Dada la definición de la aceleración:
![Page 49: MRUV](https://reader033.fdocuments.es/reader033/viewer/2022051413/559707641a28ab932f8b45da/html5/thumbnails/49.jpg)
0
0
tt
VVa f
−−
=
Dada la definición de la aceleración:
)( 00 ttaVV f −⋅=−⇒
![Page 50: MRUV](https://reader033.fdocuments.es/reader033/viewer/2022051413/559707641a28ab932f8b45da/html5/thumbnails/50.jpg)
0
0
tt
VVa f
−−
=
Dada la definición de la aceleración:
)( 00 ttaVV f −⋅=−⇒
)( 0ttaVoV f −⋅+=
![Page 51: MRUV](https://reader033.fdocuments.es/reader033/viewer/2022051413/559707641a28ab932f8b45da/html5/thumbnails/51.jpg)
0
0
tt
VVa f
−−
=
Dada la definición de la aceleración:
)( 00 ttaVV f −⋅=−⇒
)( 0ttaVoV f −⋅+=
Pero si eltiempo empieza 00 =t
![Page 52: MRUV](https://reader033.fdocuments.es/reader033/viewer/2022051413/559707641a28ab932f8b45da/html5/thumbnails/52.jpg)
0
0
tt
VVa f
−−
=
Dada la definición de la aceleración:
)( 00 ttaVV f −⋅=−⇒
)( 0ttaVoV f −⋅+=
Pero si eltiempo empieza 00 =t atVoV f +=
![Page 53: MRUV](https://reader033.fdocuments.es/reader033/viewer/2022051413/559707641a28ab932f8b45da/html5/thumbnails/53.jpg)
Vamos a utilizar:
![Page 54: MRUV](https://reader033.fdocuments.es/reader033/viewer/2022051413/559707641a28ab932f8b45da/html5/thumbnails/54.jpg)
0
0
tt
VVa f
−−
=
Vamos a utilizar:
![Page 55: MRUV](https://reader033.fdocuments.es/reader033/viewer/2022051413/559707641a28ab932f8b45da/html5/thumbnails/55.jpg)
0
0
tt
VVa f
−−
=2
2
0
tatVd
⋅+⋅=
Vamos a utilizar:
![Page 56: MRUV](https://reader033.fdocuments.es/reader033/viewer/2022051413/559707641a28ab932f8b45da/html5/thumbnails/56.jpg)
0
0
tt
VVa f
−−
=2
2
0
tatVd
⋅+⋅=
adVV f 220
2 +=
Vamos a utilizar:
![Page 57: MRUV](https://reader033.fdocuments.es/reader033/viewer/2022051413/559707641a28ab932f8b45da/html5/thumbnails/57.jpg)
0
0
tt
VVa f
−−
=2
2
0
tatVd
⋅+⋅=
adVV f 220
2 +=
Vamos a utilizar:
Del despeje de éstas, se derivan las demás