Mi lenguaje de programacion de preferencia: Programacion estructurada
programacion determinista
1
7/17/2019 programacion determinista http://slidepdf.com/reader/full/programacion-determinista 1/1 Etapa 3 F 3 (s 3 , x 3 )= 14x 3 S 3 X 3 = 0 X 3 = 1 X 3 = 2 X 3 = 3 X 4 = 4 f 3 *(S 3 ) X 3 * 0 14(0)=0 - - - - 0 0 1 14(0)=0 14(1)= 14 - - - 14 1 2 14(0)=0 14(1)= 14 14(2)= 28 - - 28 2 3 14(0)=0 14(1)= 14 14(2)= 28 14(3)= 42 - 42 3 4 14(0)=0 14(1)= 14 14(2)= 28 14(3)= 42 14(4)= 56 56 4 S 3 =0; Significa q! !" ca#i$n !st% ""!n&, 'isp&nii"i'a' '! c!& S 3 = 4; Significa q! !" ca#i$n !sta +aci&, 'isp&nii"i'a' '! 4t&n Etapa 2 f 2 (S 2 , X 2 )= 4X 2 f 3 *(s 2 -3x 2 ) S 2 X 2 = 0 X 2 = 1 f 2 *(S 2 ) X 2 * 0 4(0)0= 0 - 0 0 1 4(0)14= 14 - 14 0 2 4(0)28= 28 - 28 0 3 4(0)42= 42 4(1)0=4 4 1 4 4(0)56= 56 4(1)14= 61 61 1 Etapa 1 F 1 (S 1 , X 1 ) 31X 1 f 2 *(S 1 -2X 1 ) S 1 X 1 = 0 X 1 = 1 X 1 = 2 F 1 (S 1 ) X 1 * 0 31(0)0= 0 - - 0 0 1 31(0)14= 14 - - 14 0 2 31(0)28= 28 31(1)0= 31 - 31 1 3 31(0)4=4 31(1)14= 45 - 4 0 4 31(0)61= 61 31(1)28= 5. 31(2)0= 62 62 2 Solución: Etapa/ a'a tip& '! atc"& ac! !f!!ncia a na !tapa Esta'&/ a 'isp&nii"i'a' !sp!ct& a "a capaci'a' '!" ca#i$n !cisi$n/ antas ni'a'!s '! ca'a tip& '! atic"& ""!+a Fnci$n !csi+a/ !p!s!nta !" t&ta" '! ing!s& q! s! qi!! #axi#ia 7aa &t!n! "a s&"ci$n &pti#a, s! &s!+a q! !" #%xi#& ing!s& g!n!a'& !n "a !tapa 1, !s '!ci 62#i", s! p&'c! can'& s! '!ci'! ""!+a 2 ni'a'!s '!" atc"& 1
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7/17/2019 programacion determinista
http://slidepdf.com/reader/full/programacion-determinista 1/1
Etapa 3F3(s3, x3)= 14x3
S3 X3= 0 X3= 1 X3= 2 X3= 3 X4= 4 f 3*(S3) X3*0 14(0)=0 - - - - 0 01 14(0)=0 14(1)= 14 - - - 14 12 14(0)=0 14(1)= 14 14(2)= 28 - - 28 2
3 14(0)=0 14(1)= 14 14(2)= 28 14(3)= 42 - 42 34 14(0)=0 14(1)= 14 14(2)= 28 14(3)= 42 14(4)= 56 56 4
S3=0; Significa q! !" ca#i$n !st% ""!n&, 'isp&nii"i'a' '! c!&
S3= 4; Significa q! !" ca#i$n !sta +aci&, 'isp&nii"i'a' '! 4t&n
Etapa 2f 2(S2, X2)= 4X2 f 3*(s2-3x2)
S2 X2= 0 X2= 1 f 2*(S2) X2*
0 4(0)0= 0 - 0 01 4(0)14= 14 - 14 02 4(0)28= 28 - 28 03 4(0)42= 42 4(1)0=4 4 14 4(0)56= 56 4(1)14= 61 61 1
Etapa 1F1(S1, X1) 31X1f 2*(S1-2X1)
S1 X1= 0 X1= 1 X1= 2 F1(S1) X1*0 31(0)0= 0 - - 0 0
1 31(0)14= 14 - - 14 02 31(0)28= 28 31(1)0= 31 - 31 13 31(0)4=4 31(1)14= 45 - 4 04 31(0)61= 61 31(1)28= 5. 31(2)0= 62 62 2
Solución:
Etapa/ a'a tip& '! atc"& ac! !f!!ncia a na !tapa
Esta'&/ a 'isp&nii"i'a' !sp!ct& a "a capaci'a' '!" ca#i$n
!cisi$n/ antas ni'a'!s '! ca'a tip& '! atic"& ""!+a
Fnci$n !csi+a/ !p!s!nta !" t&ta" '! ing!s& q! s! qi!! #axi#ia
7aa &t!n! "a s&"ci$n &pti#a, s! &s!+a q! !" #%xi#& ing!s& g!n!a'& !n "a !tapa 1,
!s '!ci 62#i", s! p&'c! can'& s! '!ci'! ""!+a 2 ni'a'!s '!" atc"& 1
