Quimica de Alimm
6
ALIMENTO TIEMPO SECO FRESCO TIEMPO QUINUA HARINA PREPARADA GALLETA MANZANA PAPA 0` P PV1 = 44,3939 M 1 = 5,0187 P PV2 = 46,4067 M 2 = 5,0140 P PV1 = 37,2805 M 1 = 5,0352 P PV2 = 43,3555 M 2 = 5,0143 P PV1 = 34,6846 M 1 = 5,0121 P PV2 = 36,3498 M 2 = 5,0070 P PV1 = 43,7343 M 1 = 10,0598 P PV2 = 43,353 M 2 = 10,0508 P PV1 = 47,5139 M 1 = 10,6842 P PV2 = 37,2807 M 2 = 10,2459 0’ 25’ P 1 +M 1 = 49,0674 P 2 +M 2 = 51,0855 P 1 +M 1 = 41,9628 P 2 +M 2 = 47,9630 P 1 +M 1 = 39,6702 P 2 +M 2 = 41,3348 P 1 +M 1 = 51,3978 P 2 +M 2 = 51,6563 P 1 +M 1 = 56,8460 P 2 +M 2 = 46,4610 20` 50’ P 1 +M 1 = 48,9151 P 2 +M 2 = 50,9333 P 1 +M 1 = 41,8454 P 2 +M 2 = 47,8488 P 1 +M 1 = 39,6055 P 2 +M 2 = 42,2660 P 1 +M 1 = 49,8213 P 2 +M 2 = 49,9280 P 1 +M 1 = 56,8460 P 2 +M 2 = 43,4410 40’ 75` P 1 +M 1 = 48,8724 P 2 +M 2 = 50,8948 P 1 +M 1 = 41,8224 P 2 +M 2 = 47,8468 P 1 +M 1 = 39,6030 P 2 +M 2 = 41,2659 P 1 +M 1 = P 2 +M 2 = P 1 +M 1 = P 2 +M 2 = 60’ P 1 +M 1 = 46,2760 P 2 +M 2 = 46,3032 P 1 +M 1 = 54,2150 P 2 +M 2 = 41,0563 80` P 1 +M 1 = 45,8117 P 2 +M 2 = 45,6356 P 1 +M 1 = 53,0000 P 2 +M 2 = 40,3053 100` P 1 +M 1 = 45,6356 P 2 +M 2 = 45,2746 P 1 +M 1 = 52,1351 P 2 +M 2 = 39,7173 120` P 1 +M 1 = 45,5381 P 2 +M 2 = P 1 +M 1 = 51,3670 P 2 +M 2 = 140`
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Transcript of Quimica de Alimm
ALIMENTO TIEMPOSECOFRESCOTIEMPO
QUINUAHARINA PREPARADAGALLETAMANZANAPAPA
0`PPV1= 44,3939 M1= 5,0187PPV2= 46,4067 M2= 5,0140PPV1= 37,2805 M1= 5,0352PPV2= 43,3555 M2= 5,0143PPV1= 34,6846 M1= 5,0121PPV2= 36,3498 M2= 5,0070PPV1= 43,7343 M1= 10,0598PPV2= 43,353 M2= 10,0508PPV1= 47,5139 M1= 10,6842PPV2= 37,2807 M2= 10,24590
25P1+M1= 49,0674P2+M2= 51,0855P1+M1= 41,9628P2+M2= 47,9630P1+M1= 39,6702P2+M2= 41,3348P1+M1= 51,3978P2+M2= 51,6563P1+M1= 56,8460P2+M2= 46,461020`
50P1+M1= 48,9151P2+M2= 50,9333P1+M1= 41,8454P2+M2= 47,8488P1+M1= 39,6055P2+M2= 42,2660P1+M1= 49,8213P2+M2= 49,9280P1+M1= 56,8460P2+M2= 43,441040
75`P1+M1= 48,8724P2+M2= 50,8948P1+M1= 41,8224P2+M2= 47,8468P1+M1= 39,6030P2+M2= 41,2659P1+M1=P2+M2=P1+M1=P2+M2=60
P1+M1= 46,2760P2+M2= 46,3032P1+M1= 54,2150P2+M2= 41,056380`
P1+M1= 45,8117P2+M2= 45,6356P1+M1= 53,0000P2+M2= 40,3053100`
P1+M1= 45,6356P2+M2= 45,2746P1+M1= 52,1351P2+M2= 39,7173120`
P1+M1= 45,5381P2+M2= 45,1312P1+M1= 51,3670P2+M2= 39,2313140`
RESULTADOS
1. Determinar el porcentaje de humedad en base seca y base hmeda para cada muestra alimenticia. QUINUABase hmeda P1+M1:
Base seca P1+M1:
Base hmeda P2+M2
Base seca P2+M2:
HARINA PREPARADABase hmeda P1+M1:
Base seca P1+M1:
Base hmeda P2+M2
Base seca P2+M2:
GALLETABase hmeda P1+M1:
Base seca P1+M1
Base hmeda P2+M2
Base seca P2+M2:
MANZANABase hmeda P1+M1:
Base seca P1+M1
Base hmeda P2+M2
Base seca P2+M2:
PAPABase hmeda P1+M1:
Base seca P1+M1
Base hmeda P2+M2
Base seca P2+M2:
2. Determinar el porcentaje de materia seca de cada muestra. QUINUA:Base seca P1+M1
Base seca P2+M2
HARINA PREPARADABase seca P1+M1
Base seca P2+M2
GALLETABase seca P1+M1
Base seca P2+M2
MANZANABase seca P1+M1
Base seca P2+M2
PAPABase seca P1+M1
Base seca P2+M2
