Razones trigonométricas complementarias 5º
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Transcript of Razones trigonométricas complementarias 5º
![Page 1: Razones trigonométricas complementarias 5º](https://reader035.fdocuments.es/reader035/viewer/2022062216/55c831dbbb61eb17608b4674/html5/thumbnails/1.jpg)
RazonesTrigonométricasComplementari
as
![Page 2: Razones trigonométricas complementarias 5º](https://reader035.fdocuments.es/reader035/viewer/2022062216/55c831dbbb61eb17608b4674/html5/thumbnails/2.jpg)
Sen = CosSec = CscTg = Ctg
Donde: + = 90º
![Page 3: Razones trigonométricas complementarias 5º](https://reader035.fdocuments.es/reader035/viewer/2022062216/55c831dbbb61eb17608b4674/html5/thumbnails/3.jpg)
Halla el valor de “x” en:
Sen(x + 2º) = Cos(x – 2º)
Ejemplo 01:
![Page 4: Razones trigonométricas complementarias 5º](https://reader035.fdocuments.es/reader035/viewer/2022062216/55c831dbbb61eb17608b4674/html5/thumbnails/4.jpg)
Halla el valor de “x” en:
Tg3x = Ctg3x
Ejemplo 02:
![Page 5: Razones trigonométricas complementarias 5º](https://reader035.fdocuments.es/reader035/viewer/2022062216/55c831dbbb61eb17608b4674/html5/thumbnails/5.jpg)
Si:Tg = Ctg40ºSec = Csc70º
Halla “ + ”
Ejemplo 03:
![Page 6: Razones trigonométricas complementarias 5º](https://reader035.fdocuments.es/reader035/viewer/2022062216/55c831dbbb61eb17608b4674/html5/thumbnails/6.jpg)
Halla “x”. Sabiendo que:
Tg(8x – 9º) = Ctg3x
Ejemplo 04:
![Page 7: Razones trigonométricas complementarias 5º](https://reader035.fdocuments.es/reader035/viewer/2022062216/55c831dbbb61eb17608b4674/html5/thumbnails/7.jpg)
Halla “x”. Sabiendo que:
Sen4x – Cosx = 0
Ejemplo 05:
![Page 8: Razones trigonométricas complementarias 5º](https://reader035.fdocuments.es/reader035/viewer/2022062216/55c831dbbb61eb17608b4674/html5/thumbnails/8.jpg)
Halla “x”. Sabiendo que:
Tg3x – Ctg2x = 0
Ejemplo 06:
![Page 9: Razones trigonométricas complementarias 5º](https://reader035.fdocuments.es/reader035/viewer/2022062216/55c831dbbb61eb17608b4674/html5/thumbnails/9.jpg)
Halla “x”. Sabiendo que:
Tg(x – 9º) = Ctg2x
Ejemplo 07:
![Page 10: Razones trigonométricas complementarias 5º](https://reader035.fdocuments.es/reader035/viewer/2022062216/55c831dbbb61eb17608b4674/html5/thumbnails/10.jpg)
![Page 11: Razones trigonométricas complementarias 5º](https://reader035.fdocuments.es/reader035/viewer/2022062216/55c831dbbb61eb17608b4674/html5/thumbnails/11.jpg)
Halla “x”. Sabiendo que:
Tg7x = Ctg(2x + 9º)
Problema 01:
![Page 12: Razones trigonométricas complementarias 5º](https://reader035.fdocuments.es/reader035/viewer/2022062216/55c831dbbb61eb17608b4674/html5/thumbnails/12.jpg)
Halla “x”. Sabiendo que:
Tg(2x – 10º) = Cot(x + 40º)
Problema 02:
![Page 13: Razones trigonométricas complementarias 5º](https://reader035.fdocuments.es/reader035/viewer/2022062216/55c831dbbb61eb17608b4674/html5/thumbnails/13.jpg)
Halla “x”. Sabiendo que:
Sen(40 + 13x)º = Cos(43 + 11x)º
Problema 03:
![Page 14: Razones trigonométricas complementarias 5º](https://reader035.fdocuments.es/reader035/viewer/2022062216/55c831dbbb61eb17608b4674/html5/thumbnails/14.jpg)
Halla “x”. Sabiendo que:
Sen(y + 10º) = Cos(y + 20º)
Problema 04:
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Halla “x”. Sabiendo que:
Sec(4x – 10º) = Csc(40º – x)
Problema 05:
![Page 16: Razones trigonométricas complementarias 5º](https://reader035.fdocuments.es/reader035/viewer/2022062216/55c831dbbb61eb17608b4674/html5/thumbnails/16.jpg)
Halla “x”. Sabiendo que:
Sen(3x – 10º) = Cos(x + 10º)
Problema 06:
![Page 17: Razones trigonométricas complementarias 5º](https://reader035.fdocuments.es/reader035/viewer/2022062216/55c831dbbb61eb17608b4674/html5/thumbnails/17.jpg)
Sabiendo que:Cos(60º – x).Sec2x = 1
Sen3x = Cos3y
Halla “2y – x”
Problema 07:
![Page 18: Razones trigonométricas complementarias 5º](https://reader035.fdocuments.es/reader035/viewer/2022062216/55c831dbbb61eb17608b4674/html5/thumbnails/18.jpg)
Si:Tg7x = Ctg(2x + 9º)Sen4x . Csc3y = 1
Halla “2y – x”
Problema 08:
![Page 19: Razones trigonométricas complementarias 5º](https://reader035.fdocuments.es/reader035/viewer/2022062216/55c831dbbb61eb17608b4674/html5/thumbnails/19.jpg)
Calcula “x” e “y” si:
Tg(x + 10º).Ctg(30º + y) = 1Sen(x + 5º) = Cos(y + 5º)
Problema 09:
![Page 20: Razones trigonométricas complementarias 5º](https://reader035.fdocuments.es/reader035/viewer/2022062216/55c831dbbb61eb17608b4674/html5/thumbnails/20.jpg)
Calcula “x” e “y” si:
Cos(30º + y).Sec(x + 10º) = 1Tg(y + 5º) = Ctg(x + 5º)
Problema 10: