SOLUCIÓN
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Transcript of SOLUCIÓN
SOLUCIN PRCTICA
ALUMNO: RAMOS GOMEZ NEFER
VIGA Y LOSA INFINITAMENTE RGIDA
35
35
3
5555
0.6060
0.40
DATOS: E= 2000000.000m1=10.000Tn*Seg^2/m
m2=10.000Tn*Seg^2/m
m3=10.000Tn*Seg^2/m
Hallar. T, F y W.Solucin: Hallamos la inercia 1,2 y 3F`cEI1I2I3H1H2H3
280.0002000000.0000.0070.0070.0073.0003.0003.000
Hallamos el K1, K2, Y K3. PISO 1PISO 2PISO 3
N COL.K1N COL.K2N COL.K3
9.00057600.0009.00057600.0006.00038400.000
K1=57600.000Tn/m
K2=57600.000Tn/m
K3=38400.000Tn/m
HALLAMOS, T, F, y W.Frecuencia
f(1) = 12.079
f(2) =12.079
f(3) =9.862
Periodo
T(1) =0.083
T(2) =0.083
T(3) =0.101
P(t)1 = 50.000
P(t)2 = 20.000
P(t)3 = 10.000
w^2 (1) = 16898.124
w^2 (2) = 6982.047
w^2 (3) =1079.829
Matriz rigidez.
w1=129.993
-168981.24057600.0000.000-0.000650.000
57600.000-72981.240-38400.000X-0.0008=20.000
0.000-38400.000-130581.2400.000210.000
X = N1*sen(w*t)
x(1) =0.0006v(1) =0.017a(1) =-9.408
x(2) =0.0008v(2) =0.024a(2) =-13.330
x(3) =0.0001v(3) =0.017a(3) =-1.576
w2=83.559
-69820.47057600.0000.000-0.000450.000
57600.00026179.530-38400.000X0.0004=20.000
0.000-38400.000-31420.470-0.000810.000
X = N1*sen(w*t)
x(1) =-0.0002v(1) =-0.026a(1) =1.576
x(2) =0.0002v(2) =0.027a(2) =-1.682
x(3) =-0.0007v(3) =0.039a(3) =4.636
w3=32.861
-10798.29057600.0000.0000.000150.000
57600.00085201.710-38400.000X0.0009=20.000
0.000-38400.00027601.7100.001610.000
X = N1*sen(w*t)
x(1) =0.0000v(1) =-0.003a(1) =-0.044
x(2) =0.0004v(2) =-0.027a(2) =-0.391
x(3) =-0.0003v(3) =-0.051a(3) =0.326