Trabajo de Instalaciones
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Trabajo de Instalaciones
Transcript of Trabajo de Instalaciones
SOTANO 1
Formula:
∅ ℑ=MD (Watts)220 x cosØ
cos∅=0.9
RESOLVIENDO:
Reemplazando en la ecuación los valores obtenemos el “Im”:
∅ ℑ= 4220(Watts)220 x0.9
=21.31 Amp
Id = ØIm x 1.25 = 21.31 x 1.25 = 26.63 Amp
Id < It < Ic26.63 A < 30 A < 31 A 4mm2 = NH80
55 A4mm2 = N2XOHCABLES:
NH80 = USAMOS PARA CIRCUITOSN2XOH = USAMOS PARA ALIMENTADORES
LEYENDA:
1. 2 – 4mm2NH80 + 1 - 4mm2 NH80 (T)2. 2 - 4mm2N2XOH + 1 - 4mm2 N2XOH (T)
C1=C2=C3
RESOLVIENDO:
∅ ℑ=864 (Watts)220 x 0.9
=4.36 Amp
Id = ØIm x 1.25 = 4.36 x 1.25 = 5.45 Amp
Id < It < Ic5.45 A < 15 A < 24 A 2.5mm2 = NH80 55 A 4mm2 = N2XOH
LEYENDA:
1. 2 – 2.5mm2NH80 + 1 – 2.5mm2 NH80 (T)2. 2 - 4mm2N2XOH + 1 - 4mm2 N2XOH (T)
C4RESOLVIENDO:
∅ ℑ=432(Watts)220 x0.9
=2.18 Amp
Id = ØIm x 1.25 = 2.18 x 1.25 = 2.73 Amp
Id < It < Ic2.73 A < 15 A < 24 A 2.5mm2 = NH80 55 A 4mm2 = N2XOH
LEYENDA:
1. 2 – 2.5mm2NH80 + 1 – 2.5mm2 NH80 (T)2. 2 - 4mm2N2XOH + 1 - 4mm2 N2XOH (T)
C5
RESOLVIENDO:
∅ ℑ=216(Watts)220 x0.9
=1 .09 Amp
Id = ØIm x 1.25 = 1.09 x 1.25 = 1.36 Amp
Id < It < Ic1.36 A < 15 A < 24 A 2.5mm2 = NH80 55 A 4mm2 = N2XOH
LEYENDA:
1. 2 – 2.5mm2NH80 + 1 – 2.5mm2 NH80 (T)2. 2 - 4mm2N2XOH + 1 - 4mm2 N2XOH (T)
C6
RESOLVIENDO:
∅ ℑ=980 (Watts)220 x0.9
=4.95 Amp
Id = ØIm x 1.25 = 4.95 x 1.25 = 6.19 Amp
Id < It < Ic6.19 A < 15 A < 24 A 2.5mm2 = NH80
LEYENDA:
1. 2 – 2.5mm2NH80 + 1 – 2.5mm2 NH80 (T)
SOTANO 2Formula:
∅ ℑ=MD (Watts)220 x cosØ
cos∅=0.9
RESOLVIENDO:
Reemplazando en la ecuación los valores obtenemos el “Im”:
∅ ℑ= 4564(Watts)220 x 0.9
=23 .05 Amp
Id = ØIm x 1.25 = 23.05 x 1.25 = 28.81 Amp
Id < It < Ic28.81 A < 30 A < 31 A 4mm2 = NH80
55 A4mm2 = N2XOHCABLES:
NH80 = USAMOS PARA CIRCUITOSN2XOH = USAMOS PARA ALIMENTADORES
LEYENDA:
1. 2 – 4mm2NH80 + 1 - 4mm2 NH80 (T)2. 2 - 4mm2N2XOH + 1 - 4mm2 N2XOH (T)
C7=C8
RESOLVIENDO:
∅ ℑ=864 (Watts)220 x 0.9
=4.36 Amp
Id = ØIm x 1.25 = 4.36 x 1.25 = 5.45 Amp
Id < It < Ic5.45 A < 15 A < 24 A 2.5mm2 = NH80 55 A 4mm2 = N2XOH
LEYENDA:
1. 2 – 2.5mm2NH80 + 1 – 2.5mm2 NH80 (T)2. 2 - 4mm2N2XOH + 1 - 4mm2 N2XOH (T)
C9
RESOLVIENDO:
∅ ℑ=720(Watts)220 x0.9
=3. 64 Amp
Id = ØIm x 1.25 = 3.64 x 1.25 = 4.55 Amp
Id < It < Ic4.55 A < 15 A < 24 A 2.5mm2 = NH80 55 A 4mm2 = N2XOH
LEYENDA:
1. 2 – 2.5mm2NH80 + 1 – 2.5mm2 NH80 (T)2. 2 - 4mm2N2XOH + 1 - 4mm2 N2XOH (T)
C10
RESOLVIENDO:
∅ ℑ=576(Watts)220 x0.9
=2.91 Amp
Id = ØIm x 1.25 = 2.91 x 1.25 = 3.64 Amp
Id < It < Ic3.64 A < 15 A < 24 A 2.5mm2 = NH80 55 A 4mm2 = N2XOH
LEYENDA:
1. 2 – 2.5mm2NH80 + 1 – 2.5mm2 NH80 (T)2. 2 - 4mm2N2XOH + 1 - 4mm2 N2XOH (T)
C11
RESOLVIENDO:
∅ ℑ=1540(Watts)220 x0.9
=7.78 Amp
Id = ØIm x 1.25 = 7.78 x 1.25 = 9.73 Amp
Id < It < Ic9.73 A < 15 A < 24 A 2.5mm2 = NH80 55 A 4mm2 = N2XOH
LEYENDA:
1. 2 – 2.5mm2NH80 + 1 – 2.5mm2 NH80 (T)2. 2 - 4mm2N2XOH + 1 - 4mm2 N2XOH (T)
