Report - New ACTIVIDADES INICIALES · 2012. 2. 21. · 0 e-x (1− x)e−xdx = −(1− x)e−x −(−1)e−x +C = xe−x +C h) e3xcos xdx f g’ e3x cos x 3e3x sen x 9e3x –cos x exdxe

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