Post on 13-Dec-2015
description
Balance
(Na2 ( pi ) rLI r−Na2 (pi ) rLI r+r−Ra2 (pi )RL=dCadt
(2 ( pi ) rLr )) /(2 (pi ) rLr )
Ra=−m
dCadt
=0
( 1r ) dNa (r )dr
+m=0
Na=Ja+vzCa
Ja=−Dab( dCadr )
( 1r )(−Dab( dCadr ) ddr )+m=0
( 1r ) d2Cadr2
(−Dab ) (r )+m=0
∫ d ( dCadr )¿¿
( dCadr )(−Dab(r))=−mr2
2+C1
(−Dab(r ))∫dCa=−∫ mr22
+C 1¿dr ¿
−Dab(r )(Ca)=−mr3
6+C1 r+C2
Condiciones
1- r=R2 por flujos identicos dCadr
=0
2- r=R1Ca=Ca1
( dCadr )(−Dab(r))=−mr2
2+C1
Usando 1
C1=mR2
2
−Dab(r )(Ca)=−mr3
6+(mR22 )r+C2
C2=−Dab (r 1 ) (Ca1 )+(m )r 1[3 ]
6+(mR22 )r 1
El perfil de concentracion
Ca=(−mr36
+(mR22 )r−Dab (r 1 ) (Ca1 )+ (m )r 1[3 ]
6+(m R22 )r1)
−Dab (r )