Calculo del diámetro del eje:

Ssp {0,3×36000=10800 }

Ssp {0,18×56692,9=10204,772 }

Utilizamos el menor valor Ssp=10204,772

Asumiendo:

Km=1,5

KT=1,5

Tmax=5040lb ∙ pulg

Mmax=37476,66lb ∙ pulg

d3= 16π ×10204,772

×√ (1,5×37476,66 )2+(1,5×5040 )2

d=3,05 pulg

Hallando el diámetro del eje por resistencia

Plano y:

E×I×∫ d2 yd x2

=∫−348 x+3995 ( x−3 )+410 ( x−8 )−8114 (x−13 )+410 ( x−18 )+3995 ( x−23 )

E× I×∫ d yd x

=∫−348 x2

2+3995 ( x−3 )2

2+410 ( x−8 )2

2−8114 ( x−13 )2

2+410 ( x−18 )2

2+3995 ( x−23 )2

2+C1

E× I× y=−348 x3

6+3995 ( x−3 )3

6+410 ( x−8 )3

6−8114 ( x−13 )3

6+410 ( x−18 )3

6+3995 (x−23 )3

6+C1+C2

Sabiendo que

x=3 ; y=0

x=23 ; y=0

⇒C1=−3860,34

⇒C2=5372068

⇒E×I × ymax (x=13)=226200

Plano z:

E×I×∫ d y2

d x2=∫−127 x−65 ,5 ( x−3 )+410 ( x−8 )−435 ( x−13 )+410 ( x−18 )−65,5 ( x−23 )

E×I×∫ dydx

=∫−127 x2

2−65 ,5 ( x−3 )2

2+410 (x−8 )2

2−435 ( x−13 )2

2+410 ( x−18 )2

2−65 ,5 (x−23 )2

2+C1

E× I× y=−127 x3

6−65 ,5 ( x−3 )3

6+410 ( x−8 )3

6−435 ( x−13 )3

6+410 ( x−18 )3

6−65 ,5 (x−23 )3

6+C1+C2

Sabiendo que

x=3 ; y=0

x=23 ; y=0

⇒C1=−3818,81

⇒C2=266078,02

⇒E×I × ymax (x=13 )=88887

Si I=π ∙d4

64 y E=30×106 psi

y permisible=0,01pulgpie ( 20 pies12 )

y permisible=0,016 pulg

E×I× y=√2262002+888872

(30×106 )( π ∙d464 ) (0,016 )=340792,32

d=1,7 pulg