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Transcript of din
Solución N°1
Solución N°2
VB= VA+ X r B/A
VA =0
VB = X (173.21 i + 100 j)
VB = 173.21 j – 100 i……… (1)
VB = VC + X r B/C
VB = 100 i + X ( -229.13 i + 100 j )
VB = (100 -100 ) i – 229.13 j ……(2)
De 1 y 2
-100 = 100 -100
-0.76 =
= -0.568 rad / s
= 0.431 rad / s
āB = āA + α AB X r B/A + X ( X r B/A)
āB = α AB k X ( 173.21 i + 100 j ) + (-0.568k)x (-0.568k x ( 173 i + 100 j))
āB = (-100 α AB – 55.88 ) i + ( 173.21 α AB – 32.26 ) j ………(3)
āB = āC + α BC X r B /C + X ( X r B/C)
āB= 10i + α BC k x (-229.13 i + 100j ) + 0.431 k x ( 0.431 k x (-229.13 i + 100j ))
āB= (10 + 100 α BC + 42.57 ) i – ( 229.13 α BC + 18.58 ) j ………(4)
D e 3 y 4
α AB = -4.76 rad / s2
α BC = 3.68 rad / s2
Solución N°3
En (3)
..
M2 = ∫
M2 =
TOMANDO MOMENTO EN EL PUNTO A :
∑
M1 – Kya + kya/ 2 + 4kya + M2 = 0
-
- kya + kya / 2 + 4kya +
= 0
a) +
y = 0
b)
T = 2π /
T = 2 π (
)