Ejemplo 4.3 Smith & Vann Ness

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Transcript of Ejemplo 4.3 Smith & Vann Ness

Hoja1To =533.15Kdelta H es el cambio de entalpa para UNA MOL de sustancia (Joules / mol)To =533.15KA =3.578Q es el calor TOTAL requerido (Joules)A =3.578B =0.00302B =0.00302C =0C =0D =-18600D =-18600R =8.314J /mol KR =8.314J /mol KDeltaH =37218J /molDeltaH =37218J /molIteracinT / Ktau(B/2)*To*(t+1)MCPHT / KTtauATo*(t-1)(B/2)*To^2*(t^2-1)(D/To)*(t-1)/tICPHdelta HDiferencia112502.34455594112.6925565-0.02790959396.24264690611250.24094765571249.88554706642.34434126812564.47978740351929.7270869808-20.00562983124476.545585821237218.0000005173-0.000000517321250.24094765572.34500787332.692920331-0.02790421526.24301611581250.1985391554celda variablecelda objetivo31250.19853915542.344928332.6928562941-0.02790516176.24295113241250.2060029719Restriccin :T > To = 53341250.20600297192.34494232952.6928675645-0.02790499516.24296256941250.204689342451250.20468934242.34493986562.6928655809-0.02790502446.24296055651250.204920540561250.20492054052.34494029922.69286593-0.02790501936.24296091071250.2048798497

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