Guía 11 Derivada Implícita y Razón de Cambio
5
x cos(y) + y cos(x) − 1 = 0 dy dx sin(xy) + 3y = 4 ( π 2 , 1) sin(xy) + e xy = e x (π, 1) x 3 + y 3 = 3xy ( 3 2 , 3 2 ) 2xy − π sin(y) = 2π (1, π 2 ) 2y 3 + y 2 − y 5 = x 4 − 2x 3 + x 2 x m X v x 1 2 m(v 2 − v 2 0 ) = 1 2 k(x 2 0 − x 2 ) k, v 0 x 0 v = 0 m dv dt = − kx. d 2 x dt 2 = dv dt = a dx dt = v
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Transcript of Guía 11 Derivada Implícita y Razón de Cambio
7/18/2019 Guía 11 Derivada Implícita y Razón de Cambio
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x cos(y) + y cos(x) − 1 = 0
dydx
sin(xy) + 3y = 4 (π2
, 1)
sin(xy) + exy = ex (π, 1)
x3 + y3 = 3xy (3
2, 32
)
2xy
−π sin(y) = 2π (1, π
2)
2y3 + y2 − y5 = x4 − 2x3 + x2
x
m X v x
1
2 m(v2 − v
2
0) = 1
2 k(x2
0 −x2
)
k, v0 x0 v = 0
mdv
dt = −kx.
d2xdt2
= dvdt
= a
dxdt
= v
7/18/2019 Guía 11 Derivada Implícita y Razón de Cambio
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v s
v2 = 2gs + c g c
d2sdt2
= dvdt
= a
dsdt
= v
V
2[mh
]
1
2[mh
] V 3[m] 1[m]
100[km/h]
50[km/h]
3[m3/min]
θ(t) = 1
2 gt2
g = 32[fts2
] y P
t =
√ π
4
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x2
7 + xy2 = 4y + 8
(2, y) y > 2
x2 + 2xy − 3y2 = 0
(1, 1)
(1, 1)
L x2
3 + y2
3 = 4 (2√
2, 2√
2)
L
60[km · h−1] 25[km · h−1]
0, 5[m3 · s−1]
0, 25[m]
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AC = b CB = 2b AB = c
∠ACB = 60 B C 2[m · s−1]
A b[m] B
5[f t
·s−1]
θ
