Practica Corto
-
Upload
ryan-weaver -
Category
Documents
-
view
212 -
download
0
Transcript of Practica Corto
-
8/18/2019 Practica Corto
1/9
P(kw) FD MD(kw) FP In ITM1-MATJA 300HP 8
POLOS
243,26 0.8 194.6 0.77
2-MATJA 500HP
4POLOS
405,47 0.8 324.37
6
0.87
7-MATJA 350HP2POLOS 283,8 0.8 227.04 0.90
5-S!". A#$I F.P%0.78 295 0.85 250.75 0.78
4-&O'DOMI'IO
MD%155 FP%0.83
182 0.85 155 0.83
8-&.&OMP#TO 30 1 30 0.96 TOTAL 1439.5
3
1181.76
F.A 1.15F.P 0.85P.T!AFO("A) 1598.85P.T!AFO("A)&OM!&I
AL
1600
SOLUCIONARIO DEL EXAMEN DE INSTALACIONESELÉCTRICAS I
TEMA: CORTO CIRCUITO
1)P.n*+ +/+%1439.53
F.&%0.65
P.&/n+/ %935.69w
&/ In, I, ITM, !T, !M
1-MATJA 300H, FP%0.77, F%0.92, k%7
In1%300 x 746
√ 3 x 460 x0.77 x 0.92=396.51 A n/ (-39.64)
I1%1.2In%475.8A
ITM%3$630A
-
8/18/2019 Practica Corto
2/9
2-MATJA 500H, FP%0.87, F%0.92, k%7.4
In2%500 x 746
√ 3 x 460 x0.87 x 0.92=584.9 A
n/ (-29.54)
I1%1.2In%701.88A
ITM%3$800A
3-MATJA 350H, FP%0.9, F%0.92, k%7
In7%350 x 746
√ 3 x 460 x0.9 x0.92=395.78 A
n/ (-29.54)
I7%1.2In%474.9A
ITM%3$630A
4-S!". A#$ILIA!S
In5%295 X 10
3
√ 3 x 460 x0.78=474.68 A n/ (-38.73)
I5%1.2In%569.616A
ITM%3$630A
5-&O'DOMI'IO
In4%182.35
√ 3 x 460 x0.83=275.74 A
n/ (-33.9)
I4%1.2In%330.8A
ITM%3$400A
6-&. &OMP#TO
In4%30 X 10
3
√ 3 x 460 x0.96=39.22 A n/ (-16.26)
I4%1.2In%47.064A
ITM%3$50A
-
8/18/2019 Practica Corto
3/9
ITM%In1 In2 In7 In5 In4 In8%2155.95 n/ (-33.04)
I%1.2(2155.95) %2587.14
ITM%2500A
3) HACER EL CÁLCULO DE LA CORRIENTE DE CORTO CICUITO ENEL PUNTO A, B, C
IA%Scc
√ 3 x V n=
650 x106
√ 3 x 10 x103=37.52 kA
S% √ Icable2 x
t
k 2 %317.32::2
S%300 ::2
;
-
8/18/2019 Practica Corto
4/9
; T% (0.00580.045632)
; T% (0.00580.045632) (10
2
106 )
; T%0.36252.852=
;+/+% ;> ; T%0.48463.3=%3.335n/ (81.64)
!@= 460
;+/+%3.335(0.46
2
102 )%0.007056 n 460
I%
460
√ 3 x0.007056=37.639 kA
4. HACER EL CALCULO DE LA CORRIENTE DE CORTO CIRCUITO ENLOS PUNTOS D Y E.
HALLA'DO L IDB
ZD=ZC +Zcd
In% I(ITM7) I(ITM8) % 395.8C25.84 39.22C16.26 % 434.52C24.98
I* %1.25(434.52C24.98) % 543.15
S&&IO' 400:: → &APA&IDAD B 680 (MPL)
Vin=0.0309 x 434.52 x185 x 0.906 x 100
460 x 400=1.22≪2.5 (CUMPLE)
Vin=0.0309 x 434.52 x7 x 185 x 0.906 x100
460 x 400=8.56 ≪10 (CUMPLE)
CARACTERISTICAS N2XH TRIPLE
SECCIÓN
!SIST'&IA A&
(A)
!A&TA'&IA
(A)
AMPA&IDAD
D#&TO
-
8/18/2019 Practica Corto
5/9
NOMINAL
OME: OME:
400mm
0.0!!" 0.0#43 !$0
;% 0.185(0.06610.0943)%0.021C54.97
ZD=ZC +Zcd=0.028∨61.51
IccD= 0.46
√ 3 x0.021=12.65 KA
I&A>L ID (MPL)
HALLA'DO L IB
ZE=ZD+Zde
In % I(ITM7)% 395.8C25.84
I* %1.25(395.8C25.84) % 494.75
S&&IO' 240:: → &APA&IDAD B 525 (MPL)
Vin=0.0309 x395.8 x 45 x 0.9 x100460 x 240
=0.45≪2.5 (CUMPLE)
Vin=0.0309 x395.8 x7 x 45 x0.9 x100
460 x 240=3.14 ≪10 (CUMPLE)
CARACTERISTICAS N2XH TRIPLESECCIÓ
NNOMIN
AL
!SIST'&IA A&
(A)
!A&TA'&IA
(A)
AMPA&IDAD
D#&TOOME: OME:
240mm
0." 0.0#!% &2&
-
8/18/2019 Practica Corto
6/9
; % 0.045(0.10.0967)% 6.26 10−3∨44.04
ZE=0.034∨58.34
IccE= 0.46√ 3 x 0.034
=7.81 KA
I&A>L I (MPL)
$'C(m*+-(/ -*/1 */ * 5/( C
D+/*B
Pingre!=1439.53 G
O % 9,936
" % 460
SOL#&IO' B
"te!ric!= P ingre! ( tan#i−tan#$ ) KVAR
"te!ric!=1439,53 ( tan33,04 %−tan9.936% ) KVAR
"te!ric!=684.10 KVAR
"c!&ercial="te!ric!( V tablaV dat! )2 KVAR
"c!&ercial=684,10
(
480
460
)2 KVAR
"c!&ercial=744,88 KVAR
n+/n* /: *B
-
8/18/2019 Practica Corto
7/9
"c!&ercial=745 KVAR % 24 ' 30 "A! 1 ' 15"A! 1 ' 10 "A!
"real="c!&ercial( V dat!V tabla )2 KVAR
"real=745( 460480 )2 KVAR
"real=684,21 KVAR
I n= "real
√ 3'V =
684,21'1000
√ 3'460=858,75 A
I di I(M =1.3' I n=1,3'858,75=1116,375 A
ITM B3 ' 1250 A
I di CA)LE=1.4' I n=1,4'858,75=1202,25 A
2(3-1 ' 400::2 '2$H ) 1 ' 70::2 'H-80 2P"&-SAP O105::
P 30 "A!B
"real="c!&ercial( V dat!V tabla )2 KVAR
"real=30( 460480 )2 KVAR
"real=27,55 KVAR
I n= "real
√ 3'V =
27,55'1000
√ 3'460=34,57 A
-
8/18/2019 Practica Corto
8/9
I di I(M =1.3' I n=1,3'34,57=44,95 A
ITM B3 ' 50 A
I di CA)LE=1.4' I n=1,4'34,57=48,398 A
(3-1 ' 6::2 '2$H ) 1 ' 10::2 'H-80 2P"&-SAP O15::
P 15 "A! B
"real="c!&ercial( V dat!V tabla )2 KVAR
"real=15(460480 )2 KVAR
"real=13,77 KVAR
I n= "real
√ 3'V =
13,77'1000
√ 3'460=17,29 A
I di I(M =1.3' I n=1,3'17,29=22,47 A
ITM B3 ' 32 A
I di CA)LE=1.4' I n=1,4'17,29=24,206 A
(3-1 ' 6::2 '2$H ) 1 ' 10::2 'H-80 2P"&-SAP O15::
P 10 "A!B
"real="c!&ercial( V dat!V tabla )2 KVAR
-
8/18/2019 Practica Corto
9/9
"real=10( 460480 )2 KVAR
"real=9,184 KVAR
I n="real
√ 3'V =
9,184'1000
√ 3'460=11,526 A
I di I(M =1.3' I n=1,3'11,526=14,985 A
ITM B3 ' 16 A
I di CA)LE=1.4' I n=1,4'11,526=16,13 A
(3-1 ' 6::2 '2$H ) 1 ' 10::2 'H-80 2P"&-SAP O15::