PROBLEMAS DE ECUACIONES LINEALES
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Transcript of PROBLEMAS DE ECUACIONES LINEALES
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SOLUCIONES DEL
DEBER-2T-PROBLEMAS ECUACIONES-3
Prof. Jorge freire peña
LOGOS ACADEMY
Bachillerato Internacional
Con
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• PROBLEMA 15
• PROBLEMA 16
• PROBLEMA 18
• PROBLEMA 20
FIN
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x 200 - x200 g
+ =
cobre Plata sterling Plata sterling
mezcla
100%(x) 7.5% (200 - x) 10%(200)
100x 1500+ - 7.5 x 2000
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; x = 5.4
92.5 x = 2000 - 1500
100 x + 1500 – 7.5 x = 2000
92.5 x = 500 x = 500 / 92.5 ;
RESPUESTAS
cobre Plata sterling
5.4 g 194.6 g
REGRESAR
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5(x) 0 (100 - x) 2 (100)0
5x 200 ; x = 40
mezcla
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RESPUESTAS
40 ml 60 ml
REGRESAR
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V1 = 6 mi / h
V2 = 8 mi / h
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velocidad Tiempo X
(distancia)
Corredor 1 6mi / h t 6 t
Corredor 2 8mi / h t - 5 8(t - 5)
6 t = x
8 (t – 5) = x
6t = 8 (t – 5) = x
6t = 8t - 40
40 = 8t – 6t
40 = 2t
t = 20 minutos t - 5 = 15 minutos
Corredor 2
REGRESAR
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Norte
Sur
2 millas
x1
x2
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velocidad Tiempo (distancia)
Niño 1 4mi / h t x1 = 4 t
Niño 2 6mi / h t – 1/4 x2 = 6(t–1/4)
x = x1 + x2
2 = x1 + x2
2 = 4t + 6(t – 1/4)
x1 = 4t
x2 = 6(t – 1/4)
2 = 4t + 6t – 3/2
2+3/2 = 10t
7/2 =10t
t = 7/20 horas
t = (7/20)h *(60min/h)
t = 21 minutos
13h21REGRESAR
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REGRESAR