Post on 14-Apr-2016
description
3√8 i
√ 14 i
√2−3 i
3√8
4√54
l n (1+2 i )
t an(2π+i ln 2¿)¿
θe2xθ e−2 x
θex θsen x2
θ sen ( x )θsen (2x )
θ cos ( x )θe−x
θ cos ( x )θcos( x2 )
∮l
❑ ln z dz( z2+162 )2
; l :|z|=10
∮l
❑ cos z dz( z2+3 ) ( z−5 )3
; l :|z|=10
∮l
❑ (2−3 z+z3 )dz( z+3 )3 ( z−4 )2
; l :|z|=10
∮l
❑ cos5 x dx(x2+49 ) (x2+16 )
∮l
❑ sin x2dx
(x2+16 ) (x2+9 )