PROBLEMA 01 (MTODO DE HARDY CROSS)

Para la red mostrada en la figura calcular el caudal en cada ramal. Considerar CH = 100 para todas las tuberas.

1 Suponemos la distribucin de caudales:

2 Tabulamos nuestros calculos en la tabla siguiente:

L CH D K hfo hfo hfo/Qo hfo/Qo (hfo/Qo) Qkm pulg (valor absoluto)

BN 0.60 100.00 6.00 + 70.00 0.03367 87.22 1.25 1.25

NM 0.60 100.00 6.00 - 20.00 0.03367 -8.59 -0.43 0.43

MB 0.50 100.00 8.00 - 130.00 0.00692 -56.35 22.28 -0.43 0.43 2.11 -6

CM 0.70 100.00 8.00 - 110.00 0.00969 -57.91 -0.53 0.53

MN 0.50 100.00 6.00 + 20.00 0.02806 7.16 0.36 0.36

NC 0.60 100.00 8.00 + 90.00 0.00830 34.24 -16.51 0.38 0.38 1.26 7

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Circuito TramoQol/s

L CH D K hf hf hfo/Q hf/Q (hf/Q) Q

km pulg (valor absoluto)

BN 0.60 100.00 6.00 + 64.00 0.03367 73.90 1.15 1.15

NM 0.60 100.00 6.00 - 33.00 0.03367 -21.70 -0.66 0.66

MB 0.50 100.00 8.00 - 136.00 0.00692 -61.25 -9.05 -0.45 0.45 2.26 2

CM 0.70 100.00 8.00 - 103.00 0.00969 -51.28 -0.50 0.50

MN 0.50 100.00 6.00 + 33.00 0.02806 18.08 0.55 0.55

NC 0.60 100.00 8.00 + 97.00 0.00830 39.33 6.14 0.41 0.41 1.45 -2

L CH D K hf hf hfo/Q hf/Q (hf/Q) Q

km pulg (valor absoluto)

BN 0.60 100.00 6.00 + 66.00 0.03367 78.23 1.19 1.19

NM 0.60 100.00 6.00 - 31.00 0.03367 -19.33 -0.62 0.62

MB 0.50 100.00 8.00 - 134.00 0.00692 -59.59 -0.70 -0.44 0.44 2.25 0

CM 0.70 100.00 8.00 - 105.00 0.00969 -53.14 -0.51 0.51

MN 0.50 100.00 6.00 + 29.00 0.02806 14.24 0.49 0.49

NC 0.60 100.00 8.00 + 95.00 0.00830 37.85 -1.05 0.40 0.40 1.40 0

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Circuito TramoQ

l/s

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Circuito TramoQ

l/s

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