DISEO DE ESCALERA 1) DIMENSIONAMIENTO(Datos en metros)

2.3

m

3.44 m

2.66 m

Pasos = Contrapasos = f' c = fy = s/c = espesor del descanso = Parte Inclinada:

25 19 210 4200 400 20

cm. cm. Kg/cm2 Kg/cm2 Kg/m2 cm

t = L / 25 ~ L /20 t= 0.24 ~ t promedio = 0.27 m t adoptado = 25.00 cm

0.31 m

2) DISEO DEL PRIMER TRAMOcos a = 0.8 espesor promedio = C/2 + t/cosa espesor promedio = 0.408 Peso de la rampa = 0.979 Peso de acabados = 0.10 Carga Muerta = 1.079 Carga Muertax1.2= 1.295 Descanso: Peso del descanso= 0.48 Acabados= 0.10 Carga Muerta = 0.58 D= L= Wu=1.5D+1.8L = 1.29 Tn/m2 0.4 Tn/m2 2.66 Tn/m2

cm Tn/m Tn/m Tn/m Tn/m2 Tn/m2 Tn/m Tn/m2 2.66 Tn/m2

D= L= Wu=1.5D+1.8L = 1.59 Tn/m2

0.58 Tn/m2 0.4 Tn/m2 1.59 Tn/m2

Ra Ra = 7.49 Tn Mx = 7.49X - 2.66X^2/2 Vx =

3.44

2.66

Rb

Mx x

= 7.49 - 2.66X >>>>>>>>>

En la Ecuacion: (f*fy^2)/(2*0.85*f 'c)*As^2-f*fy*As+Mu = 0 Mu(mx) = 10.55 Ton-m As = 11.82 cm2 As min = 6.04 cm2 As a usar = 11.82 cm2 As para ancho de2.3 m = 27.19 cm2 Usar acero de 5/8 pulgada Espaciamiento efectivo = 17.31 recubrimiento lateral de 2.5 cm f de As principal Usar 14 5/8 que equivale a As(-) = As(+)/2 >= As temp As(-) = 13.595 cm2 As temp = 11.178 cm2 As (-) adoptado = 13.595 cm2 Usar acero de 1/2 pulgada Espaciamiento efectivo = 22.5 recubrimiento lateral de 2.5 cm f de As ( - ) Usar 11 1/2 que equivale a As temp en 1 m. = Long. del primer tramo = As temp en todo el tramo = 4.86 cm2 6.96 m 33.83 cm2

X= Mmax =

2.82 10.55

m. Tn - m

27.70 cm2 @

17 cm

13.93 cm2 @

23 cm

Usar acero de Espaciamiento efectivo = As temp Usar

1/2 pulgada 26.67 cm f de 27

1/2

@

26.67 cm

DISEO DE ESCALERA DE 2 TRAMOS 1) DIMENSIONAMIENTO4.00 3.44 (Datos en metros) 2.66

2.3

m 0.1 m

2.3

m

3.44 Pasos = Contrapasos = f' c = fy = s/c = espesor del descanso = Parte Inclinada: 31.27 16.52 240 4200 400 25

2.66 cm. cm. Kg/cm2 Kg/cm2 Kg/m2 cm

t = L / 25 ~ L /20 t= 0.40 t promedio = 0.45 m t adoptado = 25.00 cm

~

0.51

m

2) DISEO DEL PRIMER TRAMOcos a = 0.88 espesor promedio = C/2 + t/cosa espesor promedio = 0.367 cm Peso de la rampa = 0.881 Tn/m Peso de acabados = 0.100 Tn/m Carga Muerta = 0.981 Tn/m Carga Muerta = 1.177 Tn/m2 Descanso: Peso del descanso= 0.6 Tn/m2 Acabados= 0.10 Tn/m Carga Muerta = 0.70 Tn/m2 2.49 Tn/m2 D= L= Wu=1.5D+1.8L = 1.18 Tn/m2 0.4 Tn/m2 2.49 Tn/m2

D= L= Wu=1.5D+1.8L = 1.77 Tn/m2

0.70 Tn/m2 0.4 Tn/m2 1.77 Tn/m2

3.44 Ra Ra = 7.18 Tn Mx = 7.18X - 2.49X^2/2 Vx =

2.66 Rb

Mx x

= 7.18 - 2.49X

>>>>>>>>>

En la Ecuacion: (f*fy^2)/(2*0.85*f 'c)*As^2-f*fy*As+Mu = 0 Mu(mx) = As = As min = As a usar = As para ancho de2.3 m = Usar acero de Espaciamiento efectivo = As principal Usar 10.35 11.50 6.45 11.5 26.45 5/8 17.31 14

X= Mmax =

2.88 10.35

m. Tn - m

Ton-m cm2 0.7 f ' c b t cm2 As min = fy cm2 cm2 pulgada recubrimiento lateral de 2.5 cm f de 5/8 que equivale a

27.70 cm2

@

17.31 cm

As(-) = As(+)/2 >= As temp As(-) = 13.225 cm2 As temp = 18.63 cm2 As (-) adoptado = 18.63 cm2 Usar acero de 1/2 pulgada Espaciamiento efectivo = 16.07 recubrimiento lateral de 2.5 cm f de As ( - ) Usar 15 1/2 que equivale a As temp en 1 m. = Long. del primer tramo = As temp en todo el tramo = Usar acero de 8.10 6.57 53.21 1/2 cm2 m cm2 pulgada

18.99 cm2

@

16.07 cm

Espaciamiento efectivo = As temp Usar

15.58 cm f de 43

1/2

@

15.58 cm

2) DISEO DEL SEGUNDO TRAMOCon los valores obtenidos para el primer tramo (datos que pueden ser modificados) 2.49 Tn/m2 1.77 Tn/m2 1.77 Tn/m2

R1 4.00 3.44 2.66 obtenemos:

R2

En la ecuacion : 10.1*R2 - 1.77*(10.1*5.05) - 0.72*(3.44*5.72) = 0 R2 = 10.34 Tn R1 = 10.01 Tn Mx = 10.01X - 1.77X^2/2 - 0.72(X - 4)^2 / 2 Vx = Mmax en = Mu(max) = As = As min = As a usar = As para ancho de2.3 m = Usar acero de Espaciamiento Efectivo = As principal Usar

Mx x

= 10.01 - 1.77X - 0.72(X-4)m Tn - m cm2 cm2 cm2 cm2 pulgada recubrimiento lateral de 2.5 cm f de 5/8 que equivale a

5.177 27.6 33.95 6.45 33.95 78.09 5/8 5.77 40

79.13 cm2

@

5.77 cm

As(-) = As(+)/2 >= As temp As(-) = 39.045 cm2 As temp = 18.63 cm2 As (-) adoptado = 39.045 cm2 Usar acero de 1/2 pulgada Espaciamiento efectivo = 7.5 recubrimiento lateral de 2.5 cm f de As ( - ) Usar 31 1/2 que equivale a As temp en 1 m. = Long. del primer tramo = As temp en todo el tramo = Usar acero de Espaciamiento efectivo = As temp Usar 8.10 10.57 85.61 1/2 15.74 68 cm2 m cm2 pulgada cm f de

39.25 cm2

@

7.5 cm

1/2

@

15.74 cm

389.117647 11.50

-94500 231.36

1035000

10.10 0.72

389.117647 33.95

-94500 208.9

2760000